A) 2.496
B) 1.87
C) 2
D) 4
Correct Answer: A
Solution :
[a] \[2HI\rightleftharpoons {{H}_{2}}+{{I}_{2}}\]. is 22% decomposed, \[\therefore \frac{3.20\times 22}{100}=0.704\] \[\left( 3.2-0.704 \right)\] is equal to HI present at equilibrium which is = 2.496You need to login to perform this action.
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