A) mass of \[Ba{{O}_{2}}\]
B) mass of \[BaO\]
C) temperature of equilibrium
D) mass of \[Ba{{O}_{2}}\] and \[BaO\]both
Correct Answer: C
Solution :
[c] For the reaction \[2Ba{{O}_{2}}(s)\rightleftharpoons 2BaO(s)+{{O}_{2}}(g);\,\,\Delta H=+ve\] At equilibrium \[{{K}_{p}}={{P}_{{{O}_{2}} }}\] Hence, the value of equilibrium constant depends only upon partial pressure of \[{{O}_{2}}\]. Further on increasing temperature formation of \[{{O}_{2}}\] increases as this is an endothermic reaction. Hence, pressure of \[{{O}_{2}}\] is dependent on temperature.
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