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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    For the reaction \[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2HI(g)\] at 721 K, the value of equilibrium constant is 50, when equilibrium concentration of both is 5M. Value of \[{{K}_{p}}\] under the same conditions will be

    A) 0.02                 

    B) 0.2   

    C) 50                                

    D) 50 RT

    Correct Answer: C

    Solution :

    [c] \[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2HI(g)\] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta n}};\] \[\Delta n=2-2=0;\,\,\therefore {{K}_{p}}={{K}_{c}}\]


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