A) \[\Delta G=0,\text{ }{{Q}_{p}}>{{K}_{p}}\] the equilibrium reaction will shift from left to right
B) \[\Delta G=0,\text{ }{{Q}_{p}}={{K}_{p}}\] the equilibrium reaction will shift from left to right
C) \[\Delta G=\infty ,\text{ }{{Q}_{p}}<{{K}_{p}}\] the equilibrium reaction will shift from right to left
D) \[\Delta G<0,\text{ }{{Q}_{p}}>{{K}_{p}}\] the equilibrium reaction will shift from right to left where \[{{Q}_{p}}\] and \[{{K}_{p}}\] term refer to reaction quotient and equilibrium constant at constant pressure respectively.
Correct Answer: B
Solution :
[b] Van't Hoff reaction isotherm is \[\Delta G=\Delta G{}^\circ +RT\]In Qp When the reaction is in a state of equilibrium \[\Delta G=0\] Then \[\Delta {{G}^{{}^\circ }}=-RT\,ln\,{{Q}_{p}}=-RT\] ln \[{{K}_{p}}\]
You need to login to perform this action.
You will be redirected in
3 sec
