A) 30
B) 40
C) 80
D) 60
Correct Answer: C
Solution :
[c] \[\begin{align} & \begin{matrix} {} & {} & \,\,\,\,\,\, & {{O}_{2}}+2S{{O}_{2}}\rightleftharpoons 2S{{O}_{3}} \\ \end{matrix} \\ & \begin{matrix} \text{at}\,t=0 & {} & 1 & {} \\ \end{matrix}\,\,\,\begin{matrix} 2 & {} & {} & 0 \\ \end{matrix} \\ & \begin{matrix} \text{at}\,\text{equil}\text{.} & (1-\alpha ) & 2(1-\alpha ) & 2\alpha \\ \end{matrix} \\ \end{align}\] Given at equilibrium \[2\alpha =1.6\] \[\alpha =0.8\] \[{{K}_{C}}=\frac{{{(2\alpha )}^{2}}}{(1-\alpha ){{(2-2\alpha )}^{2}}}=\frac{{{(0.8)}^{2}}}{(1-0.8){{(1-0.8)}^{2}}}\] \[=\frac{0.64}{0.008}\] \[{{K}_{C}}=80\]You need to login to perform this action.
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