A) \[3.8\times {{10}^{-13}}\]
B) \[3.8\times {{10}^{-1}}\]
C) 6.0
D) 13.4
Correct Answer: B
Solution :
[b] \[C{{O}_{2}}+2{{H}_{2}}O\rightleftharpoons {{H}_{3}}{{O}^{+}}+HC{{O}_{3}}^{-};\] \[{{K}_{c}}=\frac{[{{H}_{3}}{{O}^{+}}][HCO_{3}^{-}]}{[C{{O}_{2}}]};\] \[\frac{[HCO_{3}^{-}]}{[C{{O}_{2}}]}=\frac{3.8\times {{10}^{-7}}}{{{10}^{-6}}}=3.8\times {{10}^{-1}}\]You need to login to perform this action.
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