A) less than 7
B) 7
C) zero
D) greater than 7
Correct Answer: B
Solution :
[b] Milliequivalents of \[NaOH=10\times 0.1=1\] Milliequivalents of \[{{H}_{2}}S{{O}_{4}}=10\times 0.05=0.5\] \[\underset{2\,equ.}{\mathop{2NaOH}}\,+\underset{1\,equ.}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}O\] \[\therefore \] 1 equivalent of \[NaOH\]reacts with 0.5 eq. of \[{{H}_{2}}S{{O}_{4}}\] to give neutral \[\left( pH=7 \right)\] solution.
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