A) 2
B) 3
C) 27
D) 36
Correct Answer: C
Solution :
[c] \[\begin{align} & \begin{matrix} {} & {} & {} & 2A{{B}_{3}}(g)\rightleftharpoons {{A}_{2}}(g)+3{{B}_{2}}(g) \\ \end{matrix} \\ & \begin{matrix} at\,t=0 & {} & 8 & \begin{matrix} {} & {} & 0 & \begin{matrix} {} & \begin{matrix} {} & 0 \\ \end{matrix} \\ \end{matrix} \\ \end{matrix} \\ \end{matrix} \\ & \begin{matrix} at\,eq. & (8-2\times 2) & {} & \begin{matrix} 2 & \begin{matrix} {} & 3\times 2 \\ \end{matrix} \\ \end{matrix} \\ \end{matrix} \\ & \begin{matrix} {} & {} & {} & \begin{matrix} =4 & {} & {} & \begin{matrix} \begin{matrix} 2 & {} & {} \\ \end{matrix} & 6 \\ \end{matrix} \\ \end{matrix} \\ \end{matrix} \\ \end{align}\] now \[{{K}_{C}}=\frac{\left[ {{A}_{2}} \right]{{\left[ {{B}_{2}} \right]}^{3}}}{{{\left[ A{{B}_{3}} \right]}^{2}}}=\frac{2/1\times {{[6/1]}^{3}}}{{{[4/1]}^{2}}}=27\]
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