2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate \[({{K}_{a}}=1.0\times {{10}^{-5}})\] will be:

    A) 5.0                   

    B) 6.0    

    C) 8.0                   

    D) 9.0

    Correct Answer: D

    Solution :

    [d] Sodium acetate is a salt of strong base and weak acid. \[\therefore pH=7+\frac{1}{2}p{{K}_{a}}=\frac{1}{2}logc\] where \[p{{K}_{a}}=-\log {{K}_{a}}=-log{{10}^{-5}}=5\] \[logc=log{{10}^{-1}}=-1\] \[pH=7+\frac{5}{2}-\frac{1}{2}=9.0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner