A) \[HC{{O}_{3}}^{-}\] is the conjugate base of\[C{{O}_{3}}^{2-}\].
B) \[N{{H}_{2}}^{-}\]is the conjugate acid of \[N{{H}_{3}}\].
C) \[{{H}_{2}}S{{O}_{4}}\] is the conjugate acid of\[HS{{O}_{4}}^{-}\].
D) \[N{{H}_{3}}\]is the conjugate base of\[N{{H}_{2}}^{-}\].
Correct Answer: C
Solution :
[c] \[HS{{O}_{4}}^{-}\] accepts a proton to form \[{{H}_{2}}S{{O}_{4}}\] Thus \[{{H}_{2}}S{{O}_{4}}\] is the conjugate acid of \[HS{{O}_{4}}^{-}\] \[\underset{base}{\mathop{HSO_{4}^{-}}}\,\xrightarrow{^{+{{H}^{+}}}}\underset{conjugate\,acid\,of\,HSO_{4}^{-}}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
