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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    One mole of \[{{O}_{2}}(g)\] and two moles of \[S{{O}_{2}}(g)\] were heated in a closed vessel of one-litre capacity at 1098 K. At equilibrium 1.6 moles of \[S{{O}_{3}}\left( g \right)\] were found. The equilibrium constant \[{{K}_{c}}\] of the reaction would be         

    A) 30                    

    B) 40    

    C) 80                                

    D) 60

    Correct Answer: C

    Solution :

    [c]          \[\begin{align}   & \begin{matrix}    {} & {} & \,\,\,\,\,\, & {{O}_{2}}+2S{{O}_{2}}\rightleftharpoons 2S{{O}_{3}}  \\ \end{matrix} \\  & \begin{matrix}    \text{at}\,t=0 & {} & 1 & {}  \\ \end{matrix}\,\,\,\begin{matrix}    2 & {} & {} & 0  \\ \end{matrix} \\  & \begin{matrix}    \text{at}\,\text{equil}\text{.} & (1-\alpha ) & 2(1-\alpha ) & 2\alpha   \\ \end{matrix} \\ \end{align}\] Given at equilibrium \[2\alpha =1.6\] \[\alpha =0.8\] \[{{K}_{C}}=\frac{{{(2\alpha )}^{2}}}{(1-\alpha ){{(2-2\alpha )}^{2}}}=\frac{{{(0.8)}^{2}}}{(1-0.8){{(1-0.8)}^{2}}}\] \[=\frac{0.64}{0.008}\] \[{{K}_{C}}=80\]


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