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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    When \[C{{O}_{2}}\] dissolves in water, the following equilibrium is established \[C{{O}_{2}}+2{{H}_{2}}O\rightleftharpoons {{H}_{3}}{{O}^{+}}+HC{{O}_{3}}^{-}\] for which the equilibrium constant is \[3.8\times {{10}^{-7}}\] and pH = 6.0. The ratio of \[\left[ HC{{O}_{3}}^{-} \right]\] to \[[C{{O}_{2}}]\] would be

    A) \[3.8\times {{10}^{-13}}\]       

    B) \[3.8\times {{10}^{-1}}\]

    C)  6.0                              

    D) 13.4

    Correct Answer: B

    Solution :

    [b] \[C{{O}_{2}}+2{{H}_{2}}O\rightleftharpoons {{H}_{3}}{{O}^{+}}+HC{{O}_{3}}^{-};\] \[{{K}_{c}}=\frac{[{{H}_{3}}{{O}^{+}}][HCO_{3}^{-}]}{[C{{O}_{2}}]};\] \[\frac{[HCO_{3}^{-}]}{[C{{O}_{2}}]}=\frac{3.8\times {{10}^{-7}}}{{{10}^{-6}}}=3.8\times {{10}^{-1}}\]


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