A) \[0.2\times {{10}^{5}}\]
B) \[5.0\times {{10}^{-5}}\]
C) \[5.0\times {{10}^{15}}\]
D) \[5.0\times {{10}^{-15}}\]
Correct Answer: D
Solution :
[d] \[{{H}_{2}}A\rightleftharpoons {{H}^{+}}+H{{A}^{-}}~\] \[\therefore {{K}_{1}}=1.0\times {{10}^{-5}}=\frac{[{{H}^{+}}][H{{A}^{-}}]}{[{{H}_{2}}A]}\] (Given) \[H{{A}^{-}}\xrightarrow{{}}{{H}^{+}}+{{A}^{2-}}\] \[\therefore {{K}_{2}}=5.0\times {{10}^{-10}}=\frac{[{{H}^{+}}][{{A}^{2-}}]}{[H{{A}^{-}}]}\] (Given) \[K=\frac{{{[{{H}^{+}}]}^{2}}[{{A}^{2-}}]}{[{{H}_{2}}A]}={{K}_{1}}\times {{K}_{2}}\] \[=\left( 1.0\times {{10}^{-5}} \right)\times \left( 5\times {{10}^{-10}} \right)=5\times {{10}^{-15}}\]
You need to login to perform this action.
You will be redirected in
3 sec
