A) 1.3
B) 2.6
C) 1.9
D) 3.4
Correct Answer: A
Solution :
[a] The pH of mixture is due to the \[HCl\] only, because \[C{{H}_{3}}COOH\] is negligibly ionised due to common ion effect. Thus, \[[{{H}^{+}}]=0.05M=5\times {{10}^{-2}}M\] \[pH=-log\left( 5\times {{10}^{-2}} \right)=-\left[ log5+log{{10}^{-2}} \right]\] \[pH=1.3\]You need to login to perform this action.
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