| (i) \[HCN(aq)+{{H}_{2}}O(l)\rightleftharpoons \] |
| \[{{H}_{3}}{{O}^{+}}(aq)+C{{N}^{-}}(aq){{K}_{a}}=6.2\times {{10}^{-10}}\] |
| (ii) \[C{{N}^{-}}(aq)+{{H}_{2}}O(l)\rightleftharpoons \] |
| \[HCN(aq)+O{{H}^{-}}(aq){{K}_{b}}=1.6\times {{10}^{-5}}.\] |
| These equilibria show the following order of the relative base strength, |
A) \[O{{H}^{-}}>{{H}_{2}}O>C{{N}^{-}}\]
B) \[O{{H}^{-}}>C{{N}^{-}}>{{H}_{2}}O\]
C) \[{{H}_{2}}O>C{{N}^{-}}>O{{H}^{-}}\]
D) \[C{{N}^{-}}>{{H}_{2}}O>O{{H}^{-}}\]
Correct Answer: B
Solution :
[b] The more is the value of equilibrium constant, the more is the completion of reaction or more is the concentration of products i.e. the order of relative strength would be \[O{{H}^{-}}>C{{N}^{-}}>{{H}_{2}}O\]
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