A) Addition of one drop of concentrated \[HCl\] in \[N{{H}_{4}}OH\] solution decreases pH of the solution.
B) A solution of the mixture of one equivalent of each of \[C{{H}_{3}}COOH\] and \[NaOH\] has a pH of 7
C) pH of pure neutral water is not zero
D) A cold and concentrated \[{{H}_{2}}S{{O}_{4}}\] has lower \[{{H}^{+}}\] ion concentration than a dilute solution of\[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: B
Solution :
[b] \[C{{H}_{3}}COOH\] is weak acid while \[NaOH\] is strong base, so one equivalent of \[NaOH\] can not be neutralized with one equivalent of \[C{{H}_{3}}COOH\]. Hence the solution of one equivalent of each does not have pH value as 7. Its pH will be towards basic side as \[NaOH\] is a strong base hence cone. of \[O{{H}^{-}}\] will be more than the cone. of \[{{H}^{+}}\].
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