JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    Why only \[A{{s}^{3+}}\] gets precipitated as \[A{{s}_{2}}{{S}_{3}}\] and not \[Z{{n}^{2+}}\]as ZnS when \[{{H}_{2}}S\] is passed through an acidic solution containing \[A{{s}^{3+}}\] and\[Z{{n}^{2+}}\]?

    A) Solubility product of \[A{{s}_{2}}{{S}_{3}}\] is less than that of ZnS

    B) Enough \[A{{s}^{3+}}\]are present in acidic medium

    C) Zinc salt does not ionise in acidic medium

    D) Solubility product changes in presence of an acid

    Correct Answer: A

    Solution :

    [a] \[{{K}_{sp}}\] of \[A{{s}_{2}}{{S}_{3}}\] is less than ZnS, In acidic medium ionisation of \[{{H}_{2}}S\] is suppressed (common ion effect) and \[{{K}_{sp}}\] of ZnS does not exceed.


You need to login to perform this action.
You will be redirected in 3 sec spinner