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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    \[NaOH\] is a strong base. What will be pH of \[5.0\times {{10}^{-2}}M\,NaOH\] solution? \[\left( log2=0.3 \right)\]

    A) 14.00               

    B) 13.70

    C) 13.00               

    D) 12.70

    Correct Answer: D

    Solution :

    [d] Given \[\left[ O{{H}^{-}} \right]=5\times {{10}^{-2}}\] \[\therefore \text{ }pOH=-log5\times {{10}^{-2}}\] \[=-log5+2log10=1.30\] \[\therefore \text{ }pH+pOH=14\] \[\therefore \text{ }pH=14-pOH\] \[=14-1.30=12.70\]


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