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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    The solubility product of \[A{{g}_{2}}Cr{{O}_{4}}\] is \[32\times {{10}^{-12}}\]. What is the concentration of \[CrO_{4}^{2-}\] ions in that solution (in g\[{{L}^{-1}}\])

    A) \[2\times {{10}^{-4}}\]                        

    B) \[8\times {{10}^{-4}}\]

    C) \[8\times {{10}^{-8}}\]                        

    D) \[16\times {{10}^{-4}}\]

    Correct Answer: A

    Solution :

    [a] For ternary electrolyte; solubility \[={{\left( \frac{{{K}_{sp}}}{4} \right)}^{\frac{1}{3}}}={{\left( \frac{32\times {{10}^{-12}}}{4} \right)}^{\frac{1}{3}}}=2\times {{10}^{-4}}\]


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