A) \[BeC{{l}_{2}}\]
B) \[SrC{{l}_{2}}\]
C) \[CaC{{l}_{2}}\]
D) \[MgC{{l}_{2}}\]
Correct Answer: A
Solution :
[a] Metal halide on hydrolysis with water form corresponding hydroxides. The basic strength of hydroxide increases as we move down in a group. This is because of the increase in size which results in decrease of ionization energy which weakens the strength of \[M-O\] bonds in MOH and thus increases, the basic strength. \[\underset{Amphoteric}{\mathop{Be{{\left( OH \right)}_{2}}}}\,~~\underset{Weak\text{ }base}{\mathop{Mg{{\left( OH \right)}_{2}}}}\,\] \[Ca{{\left( OH \right)}_{2}}\underset{Strong\text{ }base}{\mathop{Sr{{(OH)}_{2}}}}\,Ba{{\left( OH \right)}_{2}}\] Hence, \[Be{{(OH)}_{2}}\] will have lowest pH.
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