A) \[N{{H}_{4}}Cl\]
B) \[A{{l}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\]
C) \[AgN{{O}_{3}}\]
D) \[NaCN\]
Correct Answer: D
Solution :
[d] \[\underset{(Hydrolysis)}{\mathop{NaCN+{{H}_{2}}O}}\,\rightleftharpoons NaOH+HCN\] \[NaOH\] will give \[O{{H}^{-}}\] ions and react with \[{{H}^{+}}\] to form \[{{H}_{2}}O\] hence decrease the concentration of \[{{H}^{+}}\] ions.
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