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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    The dissociation constant of two acids \[H{{A}_{1}}\] and \[H{{A}_{2}}\] are \[3.14\times {{10}^{-4}}\] and \[1.96\times {{10}^{-5}}\]respectively The relative strength of the acids will be approximately

    A) 1:4                               

    B) 4:1  

    C) 1:16                             

    D) 16:1

    Correct Answer: B

    Solution :

    [b] \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}=\sqrt{\frac{{{K}_{{{a}_{1}}}}}{{{K}_{{{a}_{2}}}}}}=\sqrt{\frac{3.14\times {{10}^{-4}}}{1.96\times {{10}^{-5}}}}=4:1\]


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