2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    The partial pressure of \[C{{H}_{3}}OH(g),CO(g)\] and \[{{H}_{2}}(g)\] in equilibrium mixture for the reaction, \[CO(g)+2{{H}_{2}}(g)\rightleftharpoons C{{H}_{3}}OH(g)\] are 2.0, 1.0 and 0.1 atm respectively at \[427{}^\circ C\]. The value of \[{{K}_{p}}\] for the decomposition of \[C{{H}_{3}}OH\] to CO and \[{{H}_{2}}\] is

    A) \[{{10}^{2}}atm\]                               

    B) \[2\times {{10}^{2}}at{{m}^{-1}}\]

    C) \[50\text{ }at{{m}^{2}}\]                    

    D) \[5\times {{10}^{-3}}at{{m}^{2}}\]

    Correct Answer: D

    Solution :

    [d] \[{{K}_{p}}=\frac{{{p}_{C{{H}_{3}}OH}}}{{{p}_{CO}}\times {{p}_{{{H}_{2}}}}}=\frac{2}{1\times {{(0.1)}^{2}}}=200;\] For reverse reaction \[\frac{1}{{{K}_{p}}}=\frac{1}{200}=5\times {{10}^{-3}}at{{m}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner