A) 0.0064 g
B) 0.0128 g
C) 0.0032 g
D) None of these
Correct Answer: A
Solution :
[a] \[Ca{{C}_{2}}{{O}_{4}}\rightleftharpoons \overset{2+}{\mathop{Ca}}\,+{{C}_{2}}O_{4}^{2-};\,\,{{K}_{sp}}={{S}^{2}}\] \[\therefore S=\sqrt{{{K}_{sp}}}=\sqrt{2.5\times {{10}^{-9}}}=5\times {{10}^{-5}}mol/litre\] solubility \[=5\times {{10}^{-5}}\times 128=0.0064\text{ }g\]
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