2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    Solid \[Ba{{(N{{O}_{3}})}_{2}}\] is gradually dissolved in a  \[1.0\times {{10}^{-4}}M\,N{{a}_{2}}C{{O}_{3}}\] solution. At which concentration of \[B{{a}^{2+}}\] precipitate of \[BaC{{O}_{3}}\] begins to form? (\[{{K}_{sp}}\] for \[BaC{{O}_{3}}=5.1\times {{10}^{-9}}\])

    A) \[5.1\times {{10}^{-5}}M\]       

    B) \[7.1\times {{10}^{-8}}M\]

    C) \[4.1\times {{10}^{-5}}M\]       

    D) \[8.1\times {{10}^{-7}}M\]

    Correct Answer: A

    Solution :

    [a] Given \[N{{a}_{2}}C{{O}_{3}}=1.0\times {{10}^{-4}}M\] \[\therefore \text{ }\left[ CO_{3}^{2-} \right]=1.0\times {{10}^{-4}}M\] i.e.     \[s=1.0\times {{10}^{-4}}M\] At equilibrium \[[B{{a}^{2+}}][CO_{3}^{2-}]={{K}_{sp}}\] of \[BaC{{O}_{3}}\] \[[B{{a}^{2+}}]=\frac{{{K}_{sp}}}{[CO_{3}^{2-}]}=\frac{5.1\times {{10}^{-9}}}{1.0\times {{10}^{-4}}}\] \[=5.1\times {{10}^{-5}}M\]


You need to login to perform this action.
You will be redirected in 3 sec spinner