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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Self Evaluation Test - Equilibrium

  • question_answer
    The percentage hydrolysis of 0.15 M solution of ammonium acetate, \[{{K}_{a}}\] for \[C{{H}_{3}}COOH\]is \[1.8\times {{10}^{-5}}\] and \[{{K}_{b}}\] for \[N{{H}_{3}}\] is \[1.8\times {{10}^{-5}}\]

    A) 0.55

    B) 4.72 

    C) 9.38                 

    D) 5.56

    Correct Answer: A

    Solution :

    [a] \[\alpha =\sqrt{\frac{{{K}_{w}}}{{{K}_{a}}\times {{K}_{b}}}}\] \[=\sqrt{\frac{1\times {{10}^{-14}}}{1.8\times {{10}^{-5}}\times 1.8\times {{10}^{-5}}}}=0.55%\]%


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