A) \[1.8\times {{10}^{-6}}\]
B) \[1.8\times {{10}^{-10}}\]
C) \[2.8\times {{10}^{-10}}\]
D) \[1.0\times {{10}^{-2}}\]
Correct Answer: A
Solution :
[a] \[PbS{{O}_{4}}(s)\rightleftharpoons \] \[P{{b}^{2+}}(aq)+S{{O}_{4}}^{2-}(aq)({{K}_{sp}})\] ....(i) \[HSO_{4}^{-}(aq)\rightleftharpoons \] \[{{H}^{+}}\left( aq \right)+S{{O}_{4}}^{2-}\left( aq \right)\text{ }({{K}_{a}})\] ....(ii) Subtracting equation (ii) from (i), then \[PbS{{O}_{4}}(s)+{{H}^{+}}(aq)\rightleftharpoons \] \[P{{b}^{2+}}(aq)+HSO_{4}^{-}(aq)({{K}_{eq}})\] \[\therefore {{K}_{eq}}=\frac{{{K}_{sp}}}{{{K}_{a}}}\] \[=\frac{1.8\times {{10}^{-8}}}{1.0\times {{10}^{-2}}}=1.8\times {{10}^{-6}}\]
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