A) copper is liberated at cathode, sulphur at anode
B) copper is liberated at cathode, oxygen at anode
C) sulphur is liberated at cathode; oxygen anode
D) oxygen is liberated at cathode, copper at anode
Correct Answer: B
Solution :
[b] \[CuS{{O}_{4}}\rightleftharpoons C{{u}^{2+}}+SO_{4}^{2-}\] \[{{H}_{2}}O\rightleftharpoons {{H}^{+}}+O{{H}^{-}}\] At cathode: \[C{{u}^{2+}}+2{{e}^{-}}\to Cu\] At anode: \[4O{{H}^{-}}\to 2{{H}_{2}}O+{{O}_{2}}+4{{e}^{-}}~\]You need to login to perform this action.
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