A) 365
B) 182.5
C) 730
D) 129
Correct Answer: D
Solution :
[d] From Kepler's law of periods, \[{{T}_{2}}={{T}_{1}}{{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{3/2}}=365{{\left( \frac{/2}{{}} \right)}^{3/2}}\] \[=365\times \frac{1}{2\sqrt{2}}=129\,\operatorname{days}\]
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