A) half the present year
B) one-eighth the present year
C) one-sixth the present year
D) one-tenth the present year
Correct Answer: B
Solution :
[b] \[\frac{{{T}_{1}}^{2}}{{{T}_{2}}^{2}}=\frac{{{r}_{1}}^{3}}{{{r}_{2}}^{3}}={{\left( 4 \right)}^{3}}\] \[\therefore {{T}_{2}}={{T}_{1}}/8\]
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