A) 10
B) 100
C) \[10\sqrt{10}\]
D) 1000
Correct Answer: C
Solution :
[c] \[{{T}^{2}}\propto {{R}^{3}}\] (According to Kepler's law) \[{{T}_{1}}^{2}\propto {{\left( {{10}^{13}} \right)}^{3}}and\,\,{{T}_{2}}^{2}\propto {{\left( {{10}^{12}} \right)}^{3}}\] \[\therefore \frac{{{T}_{1}}^{2}}{{{T}_{2}}^{2}}={{\left( 10 \right)}^{3}}or\,\frac{{{T}_{1}}}{{{T}_{2}}}=10\sqrt{10}\]
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