A) 4:1
B) 3:1
C) 1:1
D) 1:2
Correct Answer: C
Solution :
[c] \[{{E}_{1}}=-\frac{G{{M}_{e}}m}{{{\operatorname{R}}_{e}}+\frac{{{\operatorname{R}}_{e}}}{2}}\left( -\frac{G{{M}_{e}}m}{{{\operatorname{R}}_{e}}} \right)=\frac{G{{M}_{e}}m}{3{{\operatorname{R}}_{e}}}\] \[{{E}_{2}}=\frac{1}{2}m{{v}_{0}}^{2}=\frac{1}{2}m.\frac{G{{M}_{e}}}{{{\operatorname{R}}_{e}}+\frac{{{\operatorname{R}}_{e}}}{2}}=\frac{G{{M}_{e}}m}{3{{\operatorname{R}}_{e}}}\] \[\therefore \frac{{{E}_{1}}}{{{E}_{2}}}=1:1\]You need to login to perform this action.
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