question_answer

Two bodies of masses 4 kg and 9 kg are separated by a distance of 60 cm. A 1 kg mass is placed in between these two masses. If the net force on 1 kg is zero, then its distance from 4 kg mass is

A) 26 cm

B) 30 cm

C) 28 cm

D) 24 cm

Correct Answer: D

Solution :

[d] \[\therefore G\frac{4\times 1}{{{x}^{2}}}=G\frac{9\times 1}{{{\left( 60-x \right)}^{2}}}\] \[or\,\,\frac{2}{3}=\frac{x}{\left( 60-x \right)}\Rightarrow x=24\,\,cm\]