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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Self Evaluation Test - Gravitation

  • question_answer
    A central particle M is surrounded by a square array of other particles, separated by either distance d or distance d/2 along the perimeter of the square. The magnitude of the gravitational force on the central particle due to the other particles is

    A) \[\frac{9GMm}{{{d}^{2}}}\]  

    B)        \[\frac{5GMm}{{{d}^{2}}}\] 

    C) \[\frac{3GMm}{{{d}^{2}}}\]  

    D)        \[\frac{GMm}{{{d}^{2}}}\]

    Correct Answer: C

    Solution :

    [c] \[F=\frac{GM\left( 3m \right)}{{{d}^{2}}}=\frac{3GMm}{{{d}^{2}}}\].


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