A)
B)
C)
D)
Correct Answer: A
Solution :
[a] \[\vec{g}=-\frac{g\vec{r}}{R}\]for\[r\le \,R\]and\[g'=\frac{g}{{{\left( 1+r/R \right)}^{2}}}\] \[r\ge R\] so option [a] is correct.
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