2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Gravitation / गुरुत्वाकर्षण

JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Self Evaluation Test - Gravitation

  • question_answer
    A particle is suspended from a spring and it stretches the spring by 1 cm on the surface of earth. By how much amount the same particle will stretch the same spring at a place 800 km above the surface of earth.

    A) 1.59 cm

    B) 2.38 cm

    C) 0.79 cm

    D) 1.38 cm

    Correct Answer: C

    Solution :

    [c] \[x={{m}_{{}^{g}/{}_{K}}}=G{{M}_{{}^{m}/{}_{{{R}^{2}}}}} k\Rightarrow x\propto \frac{1}{{{R}^{2}}}\Rightarrow {{x}_{2}}\] \[={{\left( \frac{6400}{7200} \right)}^{2}}{{x}_{1}}=0.79cm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner