A) \[g'=g/9\]
B) \[g'=27g\]
C) \[g=9g\]
D) \[g'=3g\]
Correct Answer: D
Solution :
[d] We know that \[g=\frac{GM}{{{R}^{2}}}=\frac{G\left( \frac{4}{3}\pi {{R}^{3}} \right)\rho }{{{R}^{2}}}=\frac{4}{3}g\pi GR\rho \] \[\frac{g'}{g}=\frac{R'}{R}=\frac{3R}{R}=3\therefore g'=3g\]
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