A) \[\frac{Gm}{8{{r}^{2}}}\]
B) \[\frac{Gm}{4{{r}^{2}}}\]
C) \[\sqrt{3}\frac{Gm}{8{{r}^{2}}}\]
D) \[\frac{Gm}{8{{r}^{2}}\sqrt{3}}\]
Correct Answer: C
Solution :
[c] The gravitational field due to the ring at a distance \[\sqrt{3}r\] is given by \[E=\frac{Gm(\sqrt{3})}{{{\left[ {{r}^{2}}+{{(\sqrt{3}r)}^{2}} \right]}^{3/2}}}\Rightarrow E=\frac{\sqrt{3}Gm}{8{{r}^{2}}}\]You need to login to perform this action.
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