A) Zero
B) \[\frac{G{{M}_{1}}m}{{{b}^{2}}}\]
C) \[\frac{G\left( {{M}_{1}}+{{M}_{2}} \right)m}{{{b}^{2}}}\]
D) None of these
Correct Answer: B
Solution :
[b] Gravitational force will be due to \[{{M}_{1}}\] only.You need to login to perform this action.
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