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JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Self Evaluation Test - Gravitation

  • question_answer
    R is the radius of the earth and co is its angular velocity and \[{{\operatorname{g}}_{p}}\]is the value of g at the poles. The effective value of g at the latitude \[\lambda = 60{}^\circ \] will be equal to

    A) \[{{g}_{p}}-\frac{1}{4}R{{\omega }^{2}}\]     

    B) \[{{g}_{p}}-\frac{3}{4}R{{\omega }^{2}}\]

    C) \[{{g}_{p}}-R{{\omega }^{2}}\]

    D) \[{{g}_{p}}+\frac{1}{4}R{{\omega }^{2}}\]

    Correct Answer: A

    Solution :

    [a] \[g={{g}_{p}}-R{{\omega }^{2}}{{\cos }^{2}}\lambda \] \[g={{g}_{p}}-{{\omega }^{2}}R{{\cos }^{2}}{{60}^{\operatorname{o}}}={{g}_{p}}-\frac{1}{4}R{{\omega }^{2}}\]


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