question_answer

What should be the velocity of rotation of earth due to rotation about its own axis so that the weight of a person becomes \[\frac{2}{3}\] of the present weight at the equator? Equatorial radius of the earth is R

A) \[{{\left( \frac{2g}{3R} \right)}^{\frac{1}{2}}}\]

B) \[{{\left( \frac{g}{3R} \right)}^{\frac{1}{2}}}\]

C) \[{{\left( \frac{g}{7R} \right)}^{\frac{1}{2}}}\]

D) \[{{\left( \frac{g}{5R} \right)}^{\frac{1}{2}}}\]