A) \[-6\,\,mg{{R}_{e}}\]
B) \[-0.67\,\,mg{{R}_{e}}\]
C) \[-0.99\,\,mg{{R}_{e}}\]
D) \[-0.33\,\,mg{{R}_{e}}\]
Correct Answer: B
Solution :
[b] Mass of the \[rock=m\]and height of rock from earth \[\left( h \right)= {{R}_{e}}/2 =3.2\times {{10}^{6}}m\] We know that gravitational potential energy of the rock rotating at height \[h=-\frac{G{{M}_{e}}m}{{{\operatorname{R}}_{e}}+h}=-\frac{2}{3}mg{{R}_{e}}\] \[\left( where, G{{M}_{e}}= g{{R}_{e}}^{2} and h = {{R}_{e}} \right)\]
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