A) Increases
B) decreases
C) remains constant
D) cannot say
Correct Answer: A
Solution :
[a] The gravitational potential at the centre of uniform spherical shell is equal to the gravitational potential at the surface of shell i.e., \[\operatorname{V} =\frac{-GM}{a}\], where a is radius of spherical shell Now, if the shell shrinks then its radius decrease then density increases, but mass is constant, so from above expression if a decreases, then V increases.
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