A) \[\frac{r}{2}\]
B) \[\frac{r}{2\sqrt{2}}\]
C) \[\frac{r}{{{\left( 4 \right)}^{1/3}}}\]
D) \[\frac{r}{{{\left( 2 \right)}^{1/3}}}\]
Correct Answer: C
Solution :
[c] Angular speed of earth = angular speed of geostationary satellite. If \[\omega \] is double, time period become half using \[{{T}^{2}}\propto r{{'}^{3}}r'=\frac{r}{{{4}^{1/3}}}\]
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