2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Gravitation / गुरुत्वाकर्षण

JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Self Evaluation Test - Gravitation

  • question_answer
    The gravitational field due to a mass distribution is \[\operatorname{E}=K/{{x}^{3}}\]in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

    A) \[K/x\]

    B) \[K/2x\]

    C) \[\operatorname{K}/{{x}^{2}}\]

    D) \[\operatorname{K}/2{{x}^{2}}\]

    Correct Answer: D

    Solution :

    [d]\[V=-\int_{\infty }^{x}{Edx=}\int_{\infty }^{x}{K{{x}^{-3}}dx=\frac{K}{2{{x}^{2}}}}.\].


You need to login to perform this action.
You will be redirected in 3 sec spinner