A) \[\frac{2G{{v}^{3}}}{\pi T}\]
B) \[\frac{{{v}^{3}}T}{\pi G}\]
C) \[\frac{{{v}^{3}}T}{2\pi G}\]
D) \[\frac{2T{{v}^{3}}}{\pi G}\]
Correct Answer: D
Solution :
[d] \[\frac{M{{v}^{2}}}{R}=\frac{G{{M}^{2}}}{4{{R}^{2}}}\Rightarrow M=\frac{4R{{v}^{2}}}{G}\] \[v=\frac{2\pi R}{T}\,\,\,\,\,\,\,\,\,\,\,\,R=\frac{vT}{2\pi }\,\,\,M=\frac{{{v}^{3}}T2}{\pi G}\]
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