A) 11
B) 12
C) 9
D) 10
Correct Answer: B
Solution :
[b] \[{{C}_{4}}{{H}_{7}}Cl\] is a monochloro derivative of \[{{C}_{4}}{{H}_{8}}\] which itself exists in three acyclic isomeric forms. \[\underset{\left( Its\text{ }four\text{ }C's\text{ }are\text{ }different \right)}{\mathop{\underset{I}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,}}\,\] \[\underset{\left( It\text{ }has\text{ }2\text{ }types\text{ }of\text{ }carbon \right)}{\mathop{\underset{II}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,}}\,\] \[\underset{\left( It\text{ }has\text{ }2\text{ }types\text{ }of\text{ }carbon \right)}{\mathop{\underset{III}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,}}\,\] Grand total of acyclic isomers \[=6+4+2=12\]
You need to login to perform this action.
You will be redirected in
3 sec
