A) NaI/acetone
B) NaOEt/EtOH
C) \[NaOH/{{H}_{2}}O\]
D) \[NaOH/{{H}_{2}}O-EtOH\]
Correct Answer: A
Solution :
[a] Alkyl chloride or bromide undergo substitution and get converted to an alkyl iodide on treatment with a solution of sodium iodide in acetone, e.g. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br+NaI\xrightarrow{acetone}\] \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}I+NaBr\] This reaction is also known as Finkelstein Reaction.
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