(I) Toluene |
(II) m-dichlorobenzene |
(III) o-dichlorobenzene |
(IV) p-dichlorobenzene |
A) \[I<IV<II<III\]
B) \[IV<I<II<III\]
C) \[IV<I<III<II\]
D) \[IV<II<I<III\]
Correct Answer: B
Solution :
[b] In p-dichlorobenzene, the two equal dipoles are in opposite direction, hence the molecule has zero dipole moment. In o- and m- dichlorobenzenes, the two dipoles are at \[60{}^\circ \] and \[120{}^\circ \] apart respectively, and thus according to parallelogram law offerees, the dipole moment of o-dichlorobenzene is much higher than that of m-isomer. Lastly, toluene with a +I group possesses little dipole moment. Thus the overall order isYou need to login to perform this action.
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