A) \[RI>RBr>RCl\]
B) \[RCl>RBr>RI\]
C) \[RBr>RCl>RI\]
D) \[RBr>RI>RCl\]
Correct Answer: A
Solution :
[a] For a given alkyl group, the order of reactivity is \[\xleftarrow[increasing\text{ }bond\text{ }energy]{R-I>R-Br>R-Cl>R-F}\] decreasing halogen reactivity. This order depends on the carbon-halogen bond energy; the carbon-fluorine bond energy is maximum and thus fluorides are least reactive while carbon-iodine bond energy is minimum hence iodides are most reactive,You need to login to perform this action.
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